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Albany, Wyoming
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Everything about Albany Wyoming totally explained

Albany is a census-designated place in Albany County, Wyoming, United States. The population was 80 at the 2000 census.

Geography

Albany is located at (41.180045, -106.114575).
   According to the United States Census Bureau, the CDP has a total area of 20.6 square miles (53.4 km²), of which, 20.4 square miles (52.9 km²) of it's land and 0.2 square miles (0.6 km²) of it (1.07%) is water.

Demographics

As of the census of 2000, there were 80 people, 33 households, and 22 families residing in the CDP. The population density was 3.9 people per square mile (1.5/km²). There were 99 housing units at an average density of 4.8/sq mi (1.9/km²). The racial makeup of the CDP was 92.50% White, 1.25% Asian, and 6.25% from two or more races.
   There were 33 households out of which 24.2% had children under the age of 18 living with them, 60.6% were married couples living together, 3.0% had a female householder with no husband present, and 33.3% were non-families. 21.2% of all households were made up of individuals and 3.0% had someone living alone who was 65 years of age or older. The average household size was 2.42 and the average family size was 2.91.
   In the CDP the population was spread out with 17.5% under the age of 18, 5.0% from 18 to 24, 20.0% from 25 to 44, 38.8% from 45 to 64, and 18.8% who were 65 years of age or older. The median age was 49 years. For every 100 females there were 105.1 males. For every 100 females age 18 and over, there were 100.0 males.
   The median income for a household in the CDP was $26,071, and the median income for a family was $27,321. Males had a median income of $62,321 versus $0 for females. The per capita income for the CDP was $17,046. There were no families and 9.2% of the population living below the poverty line, including no under eighteens and none of those over 64.

Further Information

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